13 May
2010
13 May
'10
2:51 p.m.
On 13/May/10 11:03, Ron Nelson wrote:
Gee, I guess you would need 6 couples to get to everyone. Thanks, Luke, for broadening my
perspective.
I'd think you'd need an odd number of pairs. Adding this idea to my
small numbers (of dancers) grab bag.
Cheers, John
J.D. Erskine
Victoria, BC
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